Solubility.cpp

/* 

    Solution by Rahul Surana

    ***********************************************************

Suppose for a unit rise in temperature, the solubility of sugar in water increases by Bg100 mL.

Chef does an experiment to check how much sugar (in g) he can dissolve given that 
he initially has 1 liter of water at X degrees and the solubility of sugar at this temperature is Ag100 mL. 
Also, Chef doesn't want to lose any water so he can increase the temperature to at most 100 degrees.

Assuming no loss of water takes place during the process, 
find the maximum amount of sugar (in g) can be dissolved in 1 liter of water under the given conditions.

Input :

The first line contains an integer T, the number of test cases. Then the test cases follow.
The only line of each test case contains three integers X,A,B.


Output :

For each testcase, output in a single line the answer to the problem.


    ***********************************************************
*/


#include <bits/stdc++.h>
#define ll          long long
#define vl          vector<ll>
#define vi          vector<int>
#define pi          pair<int,int>
#define pl          pair<ll,ll>
#define all(a)      a.begin(),a.end()
#define mem(a,x)    memset(a,x,sizeof(a))
#define pb          push_back
#define mp          make_pair
#define F           first
#define S           second
#define FOR(i,a)     for(int i = 0; i < a; i++)
#define trace(x)    cerr<<#x<<" : "<<x<<endl;
#define trace2(x,y) cerr<<#x<<" : "<<x<<" | "<<#y<<" : "<<y<<endl;
#define trace3(x,y,z) cerr<<#x<<" : "<<x<<" | "<<#y<<" : "<<y<<" | "<<#z<<" : "<<z<<endl;
#define fast_io     std::ios::sync_with_stdio(false),cin.tie(NULL),cout.tie(NULL)
#define MOD 1000000007 
using namespace std;

int main()
{
    fast_io;
    int t;
    cin >> t;
    while(t--) {
        int x,a,b;
        cin >> x >> a >> b;
        int ans = a + (100-x)*b;
        cout << ans*10<<"\n"; 
    }
}