diff --git a/theorems/T000908.md b/theorems/T000908.md new file mode 100644 index 000000000..0597188f0 --- /dev/null +++ b/theorems/T000908.md @@ -0,0 +1,13 @@ +--- +uid: T000908 +if: + and: + - P000203: true + - P000029: true +then: + P000057: true +--- + +Let $p$ be the unique non-isolated point. +By {P29}, $X$ has countably many isolated points. +Therefore $X\setminus\{p\}$ is countable, and so is $X$. diff --git a/theorems/T000909.md b/theorems/T000909.md new file mode 100644 index 000000000..aa1bfcd71 --- /dev/null +++ b/theorems/T000909.md @@ -0,0 +1,21 @@ +--- +uid: T000909 +if: + and: + - P000174: true + - P000244: true + - P000135: true +then: + P000028: true +--- + +We first handle the case where $X$ is {P2}. +Fix some point $x$; we wish to find a countable local base for $x$. Let $\mathcal{U}$ be a local base for $x$, linearly ordered by inclusion, and $\mathcal{A}$ be a countable local $\pi$-base for $x$. WLOG assume $x$ is not isolated (otherwise $\{\{x\}\}$ is a countable local base for $x$). +Therefore, for any $A \in \mathcal{A}$, there is some $a \in A \setminus \{x\}$. +By {P2} we can choose some $U_A\in\mathscr U$ that avoids the point $a$; hence $A\not\subseteq U_A$. + +Clearly, $\{U_A: A \in \mathcal{A}\}$ is a countable family of neighbourhoods of $x$; we show that it is cofinal in $\mathcal{U}$ with respect to reverse inclusion, hence a local base for $x$. +If $U \in \mathcal{U}$, there is $A \in \mathcal{A}$ with $A \subseteq U$, but since $A \not \subseteq U_A$, we cannot have $U \subseteq U_A$. By the hypothesis that $\mathcal{U}$ is linearly ordered by inclusion, we must have $U_A \subset U$ instead. +This concludes the proof for the {P2} case. + +The general case with {P135} instead of {P2} follows by passing to the Kolmogorov quotient. diff --git a/theorems/T000910.md b/theorems/T000910.md new file mode 100644 index 000000000..5fd8063e2 --- /dev/null +++ b/theorems/T000910.md @@ -0,0 +1,15 @@ +--- +uid: T000910 +if: + and: + - P000222: true + - P000244: true +then: + P000057: true +--- + +Let $x \in X$ and let $\mathcal{V}$ be a countable local $\pi$-base around $x$. +The complement of every $V\in\mathcal V$ is finite; so $W := \bigcup\{X \setminus V: V \in \mathcal{V}\}$ is countable. +For any point $y \neq x$, $X \setminus \{y\}$ is a neighbourhood of $x$ and so there is some $V \in \mathcal{V}$ with $V \subseteq X \setminus \{y\}$. +Therefore $y \in X \setminus V \subseteq W$. +It follows that $X \setminus \{x\} \subseteq W$ and $X$ is countable. diff --git a/theorems/T000911.md b/theorems/T000911.md new file mode 100644 index 000000000..dd90680d4 --- /dev/null +++ b/theorems/T000911.md @@ -0,0 +1,13 @@ +--- +uid: T000911 +if: + and: + - P000203: true + - P000081: true +then: + P000244: true +--- + +Let $p$ be the unique non-isolated point. +Then $p \in \overline{X \setminus \{p\}}$. +Let $D \subseteq X \setminus \{p\}$ be countable with $p \in \overline{D}$. Then $\{\{x\}: x \in D\}$ forms a countable local $\pi$-base for $p$. diff --git a/theorems/T000912.md b/theorems/T000912.md new file mode 100644 index 000000000..897c52c76 --- /dev/null +++ b/theorems/T000912.md @@ -0,0 +1,11 @@ +--- +uid: T000912 +if: + and: + - P000203: true + - P000167: false +then: + P000244: true +--- + +Let $p$ be the unique non-isolated point. Fix a convergent non-eventually constant sequence $(s_n: n \in \mathbb{N})$. Necessarily, its limit is $p$. By passing to a subsequence, we may assume $s_n \neq p$ for all $n$. Then $\{\{s_n\}: n \in \mathbb{N}\}$ is a countable local $\pi$-base for $p$.