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27 changes: 27 additions & 0 deletions databases/catdat/data/functors/trivial_groups.yaml
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id: trivial_groups
name: trivial functor from the category of groups
notation: $!$
source: Grp
target: '1'
description: 'Every category $\C$ has a unique functor $! : \C \to 1$ into the trivial category. Here, we specify that $\C$ is the category of groups. It is a basic example of a full functor which is not faithful.'
nlab_link: null

tags:
- algebra

related_functors:
- trivial_sets

satisfied_properties:
- property: coreflector
proof: 'The constant functor $1 \to \Grp$ with value the trivial group is a left adjoint of $! : \Grp \to 1$ and fully faithful; this is because the trivial group is an initial object of $\Grp$.'

- property: reflector
proof: 'The constant functor $1 \to \Grp$ with value the trivial group is a left adjoint of $! : \Grp \to 1$ and fully faithful; this is because $\{\ast\}$ is a terminal object of $\Grp$.'

- property: full
proof: This follows easily from the fact that <a href="/category/Grp">$\Grp$</a> is strongly connected.

unsatisfied_properties:
- property: essentially injective
proof: This is trivial.
30 changes: 30 additions & 0 deletions databases/catdat/data/functors/trivial_sets.yaml
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id: trivial_sets
name: trivial functor from the category of sets
notation: $!$
source: Set
target: '1'
description: 'Every category $\C$ has a unique functor $! : \C \to 1$ into the trivial category. Here, we specify that $\C$ is the category of sets.'
nlab_link: null

tags:
- set theory

related_functors:
- trivial_groups

satisfied_properties:
- property: coreflector
proof: 'The constant functor $1 \to \Set$ with value $\varnothing$ is a left adjoint of $! : \Set \to 1$ and fully faithful; this is because $\varnothing$ is an initial object of $\Set$.'

- property: reflector
proof: 'The constant functor $1 \to \Set$ with value $\{\ast\}$ is a left adjoint of $! : \Set \to 1$ and fully faithful; this is because $\{\ast\}$ is a terminal object of $\Set$.'

unsatisfied_properties:
- property: faithful
proof: 'Take any pair of distinct maps of sets $f,g : X \rightrightarrows Y$. They have the same image under the functor.'

- property: full
proof: If $X$ is a non-empty set, there is a (unique) morphism ${!}(X) \to {!}(\varnothing)$, but no morphism $X \to \varnothing$.

- property: essentially injective
proof: This is trivial.