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5 changes: 5 additions & 0 deletions properties/P000021.md
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Expand Up @@ -15,3 +15,8 @@ Every infinite set in $X$ has a limit point.
Equivalently, every closed discrete subset of $X$ is finite.

Defined on page 19 of {{zb:0386.54001}}.

----
#### Meta-properties

- This property is hereditary with respect to closed sets.
19 changes: 19 additions & 0 deletions spaces/S000226/README.md

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I think it may be slightly easier to avoid quotients all together (or at least as one possible construction)? I.e. a space of size aleph1 with two special points p and q such that every points except p is isloated and ....

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I'll see if I can come up with something.

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---
uid: S000226
name: Fortissimo space of size $\aleph_1$ and Sierpinski space glued at their limit points
---

$X$ is the quotient of the topological sum of {S155}
and {S10} with the two limit points identified.
In more detail, let
- $Y=$ {S155} with $p$ as non-isolated point;
- $Z=\{a,b\}$ be {S10} with $a$ as closed non-isolated point and $b$ as isolated point.

Then $X=(Y\coprod Z)/{\sim}$ with $p$ and $a$ identified.

*Note*: Both $Y$ and $Z$ embed into $X$ via the quotient map.
For ease of notation, we'll treat them as subspaces of $X$ and
also write $p$ for the common limit point in the quotient.

$X$ could also be described as extending {S155}
by adding one isolated point $b$ with $\overline{\{b\}}=\{b,p\}$.
7 changes: 7 additions & 0 deletions spaces/S000226/properties/P000002.md
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---
space: S000226
property: P000002
value: false
---

{S10} embeds into $X$ and {S10|P2}.
10 changes: 10 additions & 0 deletions spaces/S000226/properties/P000018.md
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---
space: S000226
property: P000018
value: true
---

Let $\mathscr U$ be an open cover of $X$.
There is a countable $\mathscr V\subseteq\mathscr U$ with $Y\subseteq\bigcup\mathscr V$
because {S155|P18}.
Since every neighborhood of $p$ contains $Z$, $\mathscr V$ is also a cover of $X$.
8 changes: 8 additions & 0 deletions spaces/S000226/properties/P000021.md
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---
space: S000226
property: P000021
value: false
---

$Y$ is a closed subspace of $X$
and {S155|P21}.
7 changes: 7 additions & 0 deletions spaces/S000226/properties/P000114.md
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---
space: S000226
property: P000114
value: true
---

By construction.
9 changes: 9 additions & 0 deletions spaces/S000226/properties/P000136.md
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---
space: S000226
property: P000136
value: true
---

The subspace $Y$ is closed in $X$
and anticompact ({S155|P136}).
So every compact subset of $X$ intersects $Y$ in a finite set, and is itself finite.
10 changes: 10 additions & 0 deletions spaces/S000226/properties/P000147.md
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---
space: S000226
property: P000147
value: true
---

The neighborhoods of $p$ in $X$ are the sets $V\cup Z$ with $V$ neighborhood of $p$ in $Y$.
Since {S155|P147},
$p$ is also a P-point in $X$.
And every other (isolated) point is trivially a P-point.
11 changes: 11 additions & 0 deletions spaces/S000226/properties/P000174.md
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---
space: S000226
property: P000174
value: true
---

The neighborhoods of $p$ in $X$ are the sets $V\cup Z$ with $V$ neighborhood of $p$ in $Y$.
Since {S155|P174},
there is a neighborhood base $\mathscr N$ for $p$ in $Y$ that is totally ordered by inclusion.
Then $\{V\cup Z:V\in\mathscr N\}$ is a totally ordered neighborhood base for $p$ in $X$.
And $X$ is trivially well-based at each of the other (isolated) points.
7 changes: 7 additions & 0 deletions spaces/S000226/properties/P000203.md
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---
space: S000226
property: P000203
value: true
---

All points except $p$ are isolated.
12 changes: 12 additions & 0 deletions spaces/S000226/properties/P000229.md
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---
space: S000226
property: P000229
value: true
---

The path components of $X$ are $Z$ and the singletons $\{x\}$ with $x\in Y\setminus\{p\}$
(because {S10|P37} and
every $\{x\}$ with $x\in Y\setminus\{p\}$ is clopen in $X$).

And since {S10|P229},
every path component of $X$ is {P229}.
8 changes: 8 additions & 0 deletions spaces/S000226/properties/P000234.md
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---
space: S000226
property: P000234
value: false
---

Every neighborhood $V$ of $p$ contains a point $x\in Y\setminus\{p\}$.
Hence $V$ is not connected since $\{x\}$ is clopen in $X$.
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